Syntax
- float[] sortIndices(array)
Parameters
- array—(float[], string[])Array to be sorted.
Description
The sortIndices function returns the indices of sorted values in array.
array = ["c","b","d","a"]
sortIndices(array) [3,1,0,2]
array[sortIndices(array)] ["a","b","c","d"]Duplicate values are sorted in the order of appearance.
array = [2,1,3,3,1]
sortIndices(array) [1,4,0,2,3]
array[sortIndices(array)] [1,1,2,3,3]Each row is sorted separately. The returned index array has the same dimensions as array.
array = ["e","c","d";
"b","a","c";
"d","a","d"]
sortIndices(array) [1,2,0;
4,3,5;
7,6,8]
array[sortIndices(array)] ["c","d","e";
"a","b","c";
"a","d","d"]Related
Example
Ascending and descending sorting
reverse(array) = array[size(array)-1:-1:0]
sortAsc(array) = array[sortIndices(array)]
sortDesc(array) = reverse(sortAsc(array))
const a = ["a", "c", "b"]
const b = sortAsc(a) // [a,b,c]
const c = sortDesc(a) // [c,b,a]
An array is indexed with sorted indexes which sorts all values in ascending order. The resulting array can be reversed for a descending sort order. Note that this example only applies to 1d arrays with 1 row.
Finding minimum and maximum
findMin(array) = sortIndices(array)[0]
findMax(array) = sortIndices(array)[size(array)-1]
min(array) = array[findMin(array)]
max(array) = array[findMax(array)]
const a = [1, 4, -1, 9]
const b = min(a) // -1
const c = max(a) // 9
The index of the minimum value in array is the first element in the sorted indexes array. Note that this example only applies to 1d arrays with 1 row. 2d arrays must be "flattened" first, i.e. reshaped to an array with one row:
flatten(array) = array[0:size(array)-1]
findMin(array) = sortIndices(flatten(array))[0]
findMax(array) = sortIndices(flatten(array))[size(array)-1]